3.127 \(\int \frac {\sqrt {d+e x^2} (a+b \text {csch}^{-1}(c x))}{x^6} \, dx\)

Optimal. Leaf size=527 \[ \frac {2 e \left (d+e x^2\right )^{3/2} \left (a+b \text {csch}^{-1}(c x)\right )}{15 d^2 x^3}-\frac {\left (d+e x^2\right )^{3/2} \left (a+b \text {csch}^{-1}(c x)\right )}{5 d x^5}-\frac {b c \sqrt {-c^2 x^2-1} \left (12 c^2 d+e\right ) \sqrt {d+e x^2}}{225 d x^2 \sqrt {-c^2 x^2}}+\frac {b c \sqrt {-c^2 x^2-1} \left (d+e x^2\right )^{3/2}}{25 d x^4 \sqrt {-c^2 x^2}}+\frac {b c \sqrt {-c^2 x^2-1} \left (24 c^4 d^2-19 c^2 d e-31 e^2\right ) \sqrt {d+e x^2}}{225 d^2 \sqrt {-c^2 x^2}}-\frac {b c^2 x \left (24 c^4 d^2-19 c^2 d e-31 e^2\right ) \sqrt {d+e x^2} E\left (\tan ^{-1}(c x)|1-\frac {e}{c^2 d}\right )}{225 d^2 \sqrt {-c^2 x^2} \sqrt {-c^2 x^2-1} \sqrt {\frac {d+e x^2}{d \left (c^2 x^2+1\right )}}}+\frac {2 b e x \left (6 c^4 d^2-4 c^2 d e-15 e^2\right ) \sqrt {d+e x^2} F\left (\tan ^{-1}(c x)|1-\frac {e}{c^2 d}\right )}{225 d^3 \sqrt {-c^2 x^2} \sqrt {-c^2 x^2-1} \sqrt {\frac {d+e x^2}{d \left (c^2 x^2+1\right )}}}+\frac {b c^3 x^2 \left (24 c^4 d^2-19 c^2 d e-31 e^2\right ) \sqrt {d+e x^2}}{225 d^2 \sqrt {-c^2 x^2} \sqrt {-c^2 x^2-1}} \]

[Out]

-1/5*(e*x^2+d)^(3/2)*(a+b*arccsch(c*x))/d/x^5+2/15*e*(e*x^2+d)^(3/2)*(a+b*arccsch(c*x))/d^2/x^3-1/45*b*c^3*(2*
c^2*d-e)*e*x^2*(e*x^2+d)^(1/2)/d^2/(-c^2*x^2)^(1/2)/(-c^2*x^2-1)^(1/2)-2/15*b*c^3*e^2*x^2*(e*x^2+d)^(1/2)/d^2/
(-c^2*x^2)^(1/2)/(-c^2*x^2-1)^(1/2)+1/75*b*c^3*(8*c^4*d^2-3*c^2*d*e-2*e^2)*x^2*(e*x^2+d)^(1/2)/d^2/(-c^2*x^2)^
(1/2)/(-c^2*x^2-1)^(1/2)-1/45*b*c*(2*c^2*d-e)*e*(-c^2*x^2-1)^(1/2)*(e*x^2+d)^(1/2)/d^2/(-c^2*x^2)^(1/2)-2/15*b
*c*e^2*(-c^2*x^2-1)^(1/2)*(e*x^2+d)^(1/2)/d^2/(-c^2*x^2)^(1/2)+1/75*b*c*(8*c^4*d^2-3*c^2*d*e-2*e^2)*(-c^2*x^2-
1)^(1/2)*(e*x^2+d)^(1/2)/d^2/(-c^2*x^2)^(1/2)+1/25*b*c*(-c^2*x^2-1)^(1/2)*(e*x^2+d)^(1/2)/x^4/(-c^2*x^2)^(1/2)
-1/75*b*c*(4*c^2*d-e)*(-c^2*x^2-1)^(1/2)*(e*x^2+d)^(1/2)/d/x^2/(-c^2*x^2)^(1/2)+1/45*b*c*e*(-c^2*x^2-1)^(1/2)*
(e*x^2+d)^(1/2)/d/x^2/(-c^2*x^2)^(1/2)+1/45*b*c^2*(2*c^2*d-e)*e*x*(1/(c^2*x^2+1))^(1/2)*(c^2*x^2+1)^(1/2)*Elli
pticE(c*x/(c^2*x^2+1)^(1/2),(1-e/c^2/d)^(1/2))*(e*x^2+d)^(1/2)/d^2/(-c^2*x^2)^(1/2)/(-c^2*x^2-1)^(1/2)/((e*x^2
+d)/d/(c^2*x^2+1))^(1/2)+2/15*b*c^2*e^2*x*(1/(c^2*x^2+1))^(1/2)*(c^2*x^2+1)^(1/2)*EllipticE(c*x/(c^2*x^2+1)^(1
/2),(1-e/c^2/d)^(1/2))*(e*x^2+d)^(1/2)/d^2/(-c^2*x^2)^(1/2)/(-c^2*x^2-1)^(1/2)/((e*x^2+d)/d/(c^2*x^2+1))^(1/2)
-1/75*b*c^2*(8*c^4*d^2-3*c^2*d*e-2*e^2)*x*(1/(c^2*x^2+1))^(1/2)*(c^2*x^2+1)^(1/2)*EllipticE(c*x/(c^2*x^2+1)^(1
/2),(1-e/c^2/d)^(1/2))*(e*x^2+d)^(1/2)/d^2/(-c^2*x^2)^(1/2)/(-c^2*x^2-1)^(1/2)/((e*x^2+d)/d/(c^2*x^2+1))^(1/2)
+1/75*b*c^2*(4*c^2*d-e)*e*x*(1/(c^2*x^2+1))^(1/2)*(c^2*x^2+1)^(1/2)*EllipticF(c*x/(c^2*x^2+1)^(1/2),(1-e/c^2/d
)^(1/2))*(e*x^2+d)^(1/2)/d^2/(-c^2*x^2)^(1/2)/(-c^2*x^2-1)^(1/2)/((e*x^2+d)/d/(c^2*x^2+1))^(1/2)-1/45*b*c^2*e^
2*x*(1/(c^2*x^2+1))^(1/2)*(c^2*x^2+1)^(1/2)*EllipticF(c*x/(c^2*x^2+1)^(1/2),(1-e/c^2/d)^(1/2))*(e*x^2+d)^(1/2)
/d^2/(-c^2*x^2)^(1/2)/(-c^2*x^2-1)^(1/2)/((e*x^2+d)/d/(c^2*x^2+1))^(1/2)-2/15*b*e^3*x*(1/(c^2*x^2+1))^(1/2)*(c
^2*x^2+1)^(1/2)*EllipticF(c*x/(c^2*x^2+1)^(1/2),(1-e/c^2/d)^(1/2))*(e*x^2+d)^(1/2)/d^3/(-c^2*x^2)^(1/2)/(-c^2*
x^2-1)^(1/2)/((e*x^2+d)/d/(c^2*x^2+1))^(1/2)

________________________________________________________________________________________

Rubi [A]  time = 0.64, antiderivative size = 527, normalized size of antiderivative = 1.00, number of steps used = 9, number of rules used = 10, integrand size = 23, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.435, Rules used = {271, 264, 6302, 12, 580, 583, 531, 418, 492, 411} \[ \frac {2 e \left (d+e x^2\right )^{3/2} \left (a+b \text {csch}^{-1}(c x)\right )}{15 d^2 x^3}-\frac {\left (d+e x^2\right )^{3/2} \left (a+b \text {csch}^{-1}(c x)\right )}{5 d x^5}+\frac {b c^3 x^2 \left (24 c^4 d^2-19 c^2 d e-31 e^2\right ) \sqrt {d+e x^2}}{225 d^2 \sqrt {-c^2 x^2} \sqrt {-c^2 x^2-1}}+\frac {b c \sqrt {-c^2 x^2-1} \left (24 c^4 d^2-19 c^2 d e-31 e^2\right ) \sqrt {d+e x^2}}{225 d^2 \sqrt {-c^2 x^2}}+\frac {2 b e x \left (6 c^4 d^2-4 c^2 d e-15 e^2\right ) \sqrt {d+e x^2} F\left (\tan ^{-1}(c x)|1-\frac {e}{c^2 d}\right )}{225 d^3 \sqrt {-c^2 x^2} \sqrt {-c^2 x^2-1} \sqrt {\frac {d+e x^2}{d \left (c^2 x^2+1\right )}}}-\frac {b c^2 x \left (24 c^4 d^2-19 c^2 d e-31 e^2\right ) \sqrt {d+e x^2} E\left (\tan ^{-1}(c x)|1-\frac {e}{c^2 d}\right )}{225 d^2 \sqrt {-c^2 x^2} \sqrt {-c^2 x^2-1} \sqrt {\frac {d+e x^2}{d \left (c^2 x^2+1\right )}}}+\frac {b c \sqrt {-c^2 x^2-1} \left (d+e x^2\right )^{3/2}}{25 d x^4 \sqrt {-c^2 x^2}}-\frac {b c \sqrt {-c^2 x^2-1} \left (12 c^2 d+e\right ) \sqrt {d+e x^2}}{225 d x^2 \sqrt {-c^2 x^2}} \]

Antiderivative was successfully verified.

[In]

Int[(Sqrt[d + e*x^2]*(a + b*ArcCsch[c*x]))/x^6,x]

[Out]

(b*c^3*(24*c^4*d^2 - 19*c^2*d*e - 31*e^2)*x^2*Sqrt[d + e*x^2])/(225*d^2*Sqrt[-(c^2*x^2)]*Sqrt[-1 - c^2*x^2]) +
(b*c*(24*c^4*d^2 - 19*c^2*d*e - 31*e^2)*Sqrt[-1 - c^2*x^2]*Sqrt[d + e*x^2])/(225*d^2*Sqrt[-(c^2*x^2)]) - (b*c
*(12*c^2*d + e)*Sqrt[-1 - c^2*x^2]*Sqrt[d + e*x^2])/(225*d*x^2*Sqrt[-(c^2*x^2)]) + (b*c*Sqrt[-1 - c^2*x^2]*(d
+ e*x^2)^(3/2))/(25*d*x^4*Sqrt[-(c^2*x^2)]) - ((d + e*x^2)^(3/2)*(a + b*ArcCsch[c*x]))/(5*d*x^5) + (2*e*(d + e
*x^2)^(3/2)*(a + b*ArcCsch[c*x]))/(15*d^2*x^3) - (b*c^2*(24*c^4*d^2 - 19*c^2*d*e - 31*e^2)*x*Sqrt[d + e*x^2]*E
llipticE[ArcTan[c*x], 1 - e/(c^2*d)])/(225*d^2*Sqrt[-(c^2*x^2)]*Sqrt[-1 - c^2*x^2]*Sqrt[(d + e*x^2)/(d*(1 + c^
2*x^2))]) + (2*b*e*(6*c^4*d^2 - 4*c^2*d*e - 15*e^2)*x*Sqrt[d + e*x^2]*EllipticF[ArcTan[c*x], 1 - e/(c^2*d)])/(
225*d^3*Sqrt[-(c^2*x^2)]*Sqrt[-1 - c^2*x^2]*Sqrt[(d + e*x^2)/(d*(1 + c^2*x^2))])

Rule 12

Int[(a_)*(u_), x_Symbol] :> Dist[a, Int[u, x], x] /; FreeQ[a, x] &&  !MatchQ[u, (b_)*(v_) /; FreeQ[b, x]]

Rule 264

Int[((c_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Simp[((c*x)^(m + 1)*(a + b*x^n)^(p + 1))/(a
*c*(m + 1)), x] /; FreeQ[{a, b, c, m, n, p}, x] && EqQ[(m + 1)/n + p + 1, 0] && NeQ[m, -1]

Rule 271

Int[(x_)^(m_)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Simp[(x^(m + 1)*(a + b*x^n)^(p + 1))/(a*(m + 1)), x]
- Dist[(b*(m + n*(p + 1) + 1))/(a*(m + 1)), Int[x^(m + n)*(a + b*x^n)^p, x], x] /; FreeQ[{a, b, m, n, p}, x]
&& ILtQ[Simplify[(m + 1)/n + p + 1], 0] && NeQ[m, -1]

Rule 411

Int[Sqrt[(a_) + (b_.)*(x_)^2]/((c_) + (d_.)*(x_)^2)^(3/2), x_Symbol] :> Simp[(Sqrt[a + b*x^2]*EllipticE[ArcTan
[Rt[d/c, 2]*x], 1 - (b*c)/(a*d)])/(c*Rt[d/c, 2]*Sqrt[c + d*x^2]*Sqrt[(c*(a + b*x^2))/(a*(c + d*x^2))]), x] /;
FreeQ[{a, b, c, d}, x] && PosQ[b/a] && PosQ[d/c]

Rule 418

Int[1/(Sqrt[(a_) + (b_.)*(x_)^2]*Sqrt[(c_) + (d_.)*(x_)^2]), x_Symbol] :> Simp[(Sqrt[a + b*x^2]*EllipticF[ArcT
an[Rt[d/c, 2]*x], 1 - (b*c)/(a*d)])/(a*Rt[d/c, 2]*Sqrt[c + d*x^2]*Sqrt[(c*(a + b*x^2))/(a*(c + d*x^2))]), x] /
; FreeQ[{a, b, c, d}, x] && PosQ[d/c] && PosQ[b/a] &&  !SimplerSqrtQ[b/a, d/c]

Rule 492

Int[(x_)^2/(Sqrt[(a_) + (b_.)*(x_)^2]*Sqrt[(c_) + (d_.)*(x_)^2]), x_Symbol] :> Simp[(x*Sqrt[a + b*x^2])/(b*Sqr
t[c + d*x^2]), x] - Dist[c/b, Int[Sqrt[a + b*x^2]/(c + d*x^2)^(3/2), x], x] /; FreeQ[{a, b, c, d}, x] && NeQ[b
*c - a*d, 0] && PosQ[b/a] && PosQ[d/c] &&  !SimplerSqrtQ[b/a, d/c]

Rule 531

Int[((a_) + (b_.)*(x_)^(n_))^(p_.)*((c_) + (d_.)*(x_)^(n_))^(q_.)*((e_) + (f_.)*(x_)^(n_)), x_Symbol] :> Dist[
e, Int[(a + b*x^n)^p*(c + d*x^n)^q, x], x] + Dist[f, Int[x^n*(a + b*x^n)^p*(c + d*x^n)^q, x], x] /; FreeQ[{a,
b, c, d, e, f, n, p, q}, x]

Rule 580

Int[((g_.)*(x_))^(m_)*((a_) + (b_.)*(x_)^(n_))^(p_.)*((c_) + (d_.)*(x_)^(n_))^(q_.)*((e_) + (f_.)*(x_)^(n_)),
x_Symbol] :> Simp[(e*(g*x)^(m + 1)*(a + b*x^n)^(p + 1)*(c + d*x^n)^q)/(a*g*(m + 1)), x] - Dist[1/(a*g^n*(m + 1
)), Int[(g*x)^(m + n)*(a + b*x^n)^p*(c + d*x^n)^(q - 1)*Simp[c*(b*e - a*f)*(m + 1) + e*n*(b*c*(p + 1) + a*d*q)
+ d*((b*e - a*f)*(m + 1) + b*e*n*(p + q + 1))*x^n, x], x], x] /; FreeQ[{a, b, c, d, e, f, g, p}, x] && IGtQ[n
, 0] && GtQ[q, 0] && LtQ[m, -1] &&  !(EqQ[q, 1] && SimplerQ[e + f*x^n, c + d*x^n])

Rule 583

Int[((g_.)*(x_))^(m_)*((a_) + (b_.)*(x_)^(n_))^(p_.)*((c_) + (d_.)*(x_)^(n_))^(q_.)*((e_) + (f_.)*(x_)^(n_)),
x_Symbol] :> Simp[(e*(g*x)^(m + 1)*(a + b*x^n)^(p + 1)*(c + d*x^n)^(q + 1))/(a*c*g*(m + 1)), x] + Dist[1/(a*c*
g^n*(m + 1)), Int[(g*x)^(m + n)*(a + b*x^n)^p*(c + d*x^n)^q*Simp[a*f*c*(m + 1) - e*(b*c + a*d)*(m + n + 1) - e
*n*(b*c*p + a*d*q) - b*e*d*(m + n*(p + q + 2) + 1)*x^n, x], x], x] /; FreeQ[{a, b, c, d, e, f, g, p, q}, x] &&
IGtQ[n, 0] && LtQ[m, -1]

Rule 6302

Int[((a_.) + ArcCsch[(c_.)*(x_)]*(b_.))*((f_.)*(x_))^(m_.)*((d_.) + (e_.)*(x_)^2)^(p_.), x_Symbol] :> With[{u
= IntHide[(f*x)^m*(d + e*x^2)^p, x]}, Dist[a + b*ArcCsch[c*x], u, x] - Dist[(b*c*x)/Sqrt[-(c^2*x^2)], Int[Simp
lifyIntegrand[u/(x*Sqrt[-1 - c^2*x^2]), x], x], x]] /; FreeQ[{a, b, c, d, e, f, m, p}, x] && ((IGtQ[p, 0] &&
!(ILtQ[(m - 1)/2, 0] && GtQ[m + 2*p + 3, 0])) || (IGtQ[(m + 1)/2, 0] &&  !(ILtQ[p, 0] && GtQ[m + 2*p + 3, 0]))
|| (ILtQ[(m + 2*p + 1)/2, 0] &&  !ILtQ[(m - 1)/2, 0]))

Rubi steps

\begin {align*} \int \frac {\sqrt {d+e x^2} \left (a+b \text {csch}^{-1}(c x)\right )}{x^6} \, dx &=-\frac {\left (d+e x^2\right )^{3/2} \left (a+b \text {csch}^{-1}(c x)\right )}{5 d x^5}+\frac {2 e \left (d+e x^2\right )^{3/2} \left (a+b \text {csch}^{-1}(c x)\right )}{15 d^2 x^3}-\frac {(b c x) \int \frac {\left (d+e x^2\right )^{3/2} \left (-3 d+2 e x^2\right )}{15 d^2 x^6 \sqrt {-1-c^2 x^2}} \, dx}{\sqrt {-c^2 x^2}}\\ &=-\frac {\left (d+e x^2\right )^{3/2} \left (a+b \text {csch}^{-1}(c x)\right )}{5 d x^5}+\frac {2 e \left (d+e x^2\right )^{3/2} \left (a+b \text {csch}^{-1}(c x)\right )}{15 d^2 x^3}-\frac {(b c x) \int \frac {\left (d+e x^2\right )^{3/2} \left (-3 d+2 e x^2\right )}{x^6 \sqrt {-1-c^2 x^2}} \, dx}{15 d^2 \sqrt {-c^2 x^2}}\\ &=\frac {b c \sqrt {-1-c^2 x^2} \left (d+e x^2\right )^{3/2}}{25 d x^4 \sqrt {-c^2 x^2}}-\frac {\left (d+e x^2\right )^{3/2} \left (a+b \text {csch}^{-1}(c x)\right )}{5 d x^5}+\frac {2 e \left (d+e x^2\right )^{3/2} \left (a+b \text {csch}^{-1}(c x)\right )}{15 d^2 x^3}+\frac {(b c x) \int \frac {\sqrt {d+e x^2} \left (-d \left (12 c^2 d+e\right )-e \left (3 c^2 d+10 e\right ) x^2\right )}{x^4 \sqrt {-1-c^2 x^2}} \, dx}{75 d^2 \sqrt {-c^2 x^2}}\\ &=-\frac {b c \left (12 c^2 d+e\right ) \sqrt {-1-c^2 x^2} \sqrt {d+e x^2}}{225 d x^2 \sqrt {-c^2 x^2}}+\frac {b c \sqrt {-1-c^2 x^2} \left (d+e x^2\right )^{3/2}}{25 d x^4 \sqrt {-c^2 x^2}}-\frac {\left (d+e x^2\right )^{3/2} \left (a+b \text {csch}^{-1}(c x)\right )}{5 d x^5}+\frac {2 e \left (d+e x^2\right )^{3/2} \left (a+b \text {csch}^{-1}(c x)\right )}{15 d^2 x^3}-\frac {(b c x) \int \frac {-d \left (24 c^4 d^2-19 c^2 d e-31 e^2\right )-2 e \left (6 c^4 d^2-4 c^2 d e-15 e^2\right ) x^2}{x^2 \sqrt {-1-c^2 x^2} \sqrt {d+e x^2}} \, dx}{225 d^2 \sqrt {-c^2 x^2}}\\ &=\frac {b c \left (24 c^4 d^2-19 c^2 d e-31 e^2\right ) \sqrt {-1-c^2 x^2} \sqrt {d+e x^2}}{225 d^2 \sqrt {-c^2 x^2}}-\frac {b c \left (12 c^2 d+e\right ) \sqrt {-1-c^2 x^2} \sqrt {d+e x^2}}{225 d x^2 \sqrt {-c^2 x^2}}+\frac {b c \sqrt {-1-c^2 x^2} \left (d+e x^2\right )^{3/2}}{25 d x^4 \sqrt {-c^2 x^2}}-\frac {\left (d+e x^2\right )^{3/2} \left (a+b \text {csch}^{-1}(c x)\right )}{5 d x^5}+\frac {2 e \left (d+e x^2\right )^{3/2} \left (a+b \text {csch}^{-1}(c x)\right )}{15 d^2 x^3}-\frac {(b c x) \int \frac {-2 d e \left (6 c^4 d^2-4 c^2 d e-15 e^2\right )-c^2 d e \left (24 c^4 d^2-19 c^2 d e-31 e^2\right ) x^2}{\sqrt {-1-c^2 x^2} \sqrt {d+e x^2}} \, dx}{225 d^3 \sqrt {-c^2 x^2}}\\ &=\frac {b c \left (24 c^4 d^2-19 c^2 d e-31 e^2\right ) \sqrt {-1-c^2 x^2} \sqrt {d+e x^2}}{225 d^2 \sqrt {-c^2 x^2}}-\frac {b c \left (12 c^2 d+e\right ) \sqrt {-1-c^2 x^2} \sqrt {d+e x^2}}{225 d x^2 \sqrt {-c^2 x^2}}+\frac {b c \sqrt {-1-c^2 x^2} \left (d+e x^2\right )^{3/2}}{25 d x^4 \sqrt {-c^2 x^2}}-\frac {\left (d+e x^2\right )^{3/2} \left (a+b \text {csch}^{-1}(c x)\right )}{5 d x^5}+\frac {2 e \left (d+e x^2\right )^{3/2} \left (a+b \text {csch}^{-1}(c x)\right )}{15 d^2 x^3}+\frac {\left (b c^3 e \left (24 c^4 d^2-19 c^2 d e-31 e^2\right ) x\right ) \int \frac {x^2}{\sqrt {-1-c^2 x^2} \sqrt {d+e x^2}} \, dx}{225 d^2 \sqrt {-c^2 x^2}}+\frac {\left (2 b c e \left (6 c^4 d^2-4 c^2 d e-15 e^2\right ) x\right ) \int \frac {1}{\sqrt {-1-c^2 x^2} \sqrt {d+e x^2}} \, dx}{225 d^2 \sqrt {-c^2 x^2}}\\ &=\frac {b c^3 \left (24 c^4 d^2-19 c^2 d e-31 e^2\right ) x^2 \sqrt {d+e x^2}}{225 d^2 \sqrt {-c^2 x^2} \sqrt {-1-c^2 x^2}}+\frac {b c \left (24 c^4 d^2-19 c^2 d e-31 e^2\right ) \sqrt {-1-c^2 x^2} \sqrt {d+e x^2}}{225 d^2 \sqrt {-c^2 x^2}}-\frac {b c \left (12 c^2 d+e\right ) \sqrt {-1-c^2 x^2} \sqrt {d+e x^2}}{225 d x^2 \sqrt {-c^2 x^2}}+\frac {b c \sqrt {-1-c^2 x^2} \left (d+e x^2\right )^{3/2}}{25 d x^4 \sqrt {-c^2 x^2}}-\frac {\left (d+e x^2\right )^{3/2} \left (a+b \text {csch}^{-1}(c x)\right )}{5 d x^5}+\frac {2 e \left (d+e x^2\right )^{3/2} \left (a+b \text {csch}^{-1}(c x)\right )}{15 d^2 x^3}+\frac {2 b e \left (6 c^4 d^2-4 c^2 d e-15 e^2\right ) x \sqrt {d+e x^2} F\left (\tan ^{-1}(c x)|1-\frac {e}{c^2 d}\right )}{225 d^3 \sqrt {-c^2 x^2} \sqrt {-1-c^2 x^2} \sqrt {\frac {d+e x^2}{d \left (1+c^2 x^2\right )}}}+\frac {\left (b c^3 \left (24 c^4 d^2-19 c^2 d e-31 e^2\right ) x\right ) \int \frac {\sqrt {d+e x^2}}{\left (-1-c^2 x^2\right )^{3/2}} \, dx}{225 d^2 \sqrt {-c^2 x^2}}\\ &=\frac {b c^3 \left (24 c^4 d^2-19 c^2 d e-31 e^2\right ) x^2 \sqrt {d+e x^2}}{225 d^2 \sqrt {-c^2 x^2} \sqrt {-1-c^2 x^2}}+\frac {b c \left (24 c^4 d^2-19 c^2 d e-31 e^2\right ) \sqrt {-1-c^2 x^2} \sqrt {d+e x^2}}{225 d^2 \sqrt {-c^2 x^2}}-\frac {b c \left (12 c^2 d+e\right ) \sqrt {-1-c^2 x^2} \sqrt {d+e x^2}}{225 d x^2 \sqrt {-c^2 x^2}}+\frac {b c \sqrt {-1-c^2 x^2} \left (d+e x^2\right )^{3/2}}{25 d x^4 \sqrt {-c^2 x^2}}-\frac {\left (d+e x^2\right )^{3/2} \left (a+b \text {csch}^{-1}(c x)\right )}{5 d x^5}+\frac {2 e \left (d+e x^2\right )^{3/2} \left (a+b \text {csch}^{-1}(c x)\right )}{15 d^2 x^3}-\frac {b c^2 \left (24 c^4 d^2-19 c^2 d e-31 e^2\right ) x \sqrt {d+e x^2} E\left (\tan ^{-1}(c x)|1-\frac {e}{c^2 d}\right )}{225 d^2 \sqrt {-c^2 x^2} \sqrt {-1-c^2 x^2} \sqrt {\frac {d+e x^2}{d \left (1+c^2 x^2\right )}}}+\frac {2 b e \left (6 c^4 d^2-4 c^2 d e-15 e^2\right ) x \sqrt {d+e x^2} F\left (\tan ^{-1}(c x)|1-\frac {e}{c^2 d}\right )}{225 d^3 \sqrt {-c^2 x^2} \sqrt {-1-c^2 x^2} \sqrt {\frac {d+e x^2}{d \left (1+c^2 x^2\right )}}}\\ \end {align*}

________________________________________________________________________________________

Mathematica [C]  time = 0.70, size = 314, normalized size = 0.60 \[ \frac {\sqrt {d+e x^2} \left (-15 a \left (3 d^2+d e x^2-2 e^2 x^4\right )+b c x \sqrt {\frac {1}{c^2 x^2}+1} \left (d e x^2 \left (8-19 c^2 x^2\right )+3 d^2 \left (8 c^4 x^4-4 c^2 x^2+3\right )-31 e^2 x^4\right )-15 b \text {csch}^{-1}(c x) \left (3 d^2+d e x^2-2 e^2 x^4\right )\right )}{225 d^2 x^5}+\frac {i b c x \sqrt {\frac {1}{c^2 x^2}+1} \sqrt {\frac {e x^2}{d}+1} \left (c^2 d \left (24 c^4 d^2-19 c^2 d e-31 e^2\right ) E\left (i \sinh ^{-1}\left (\sqrt {c^2} x\right )|\frac {e}{c^2 d}\right )+\left (-24 c^6 d^3+31 c^4 d^2 e+23 c^2 d e^2-30 e^3\right ) F\left (i \sinh ^{-1}\left (\sqrt {c^2} x\right )|\frac {e}{c^2 d}\right )\right )}{225 \sqrt {c^2} d^2 \sqrt {c^2 x^2+1} \sqrt {d+e x^2}} \]

Antiderivative was successfully verified.

[In]

Integrate[(Sqrt[d + e*x^2]*(a + b*ArcCsch[c*x]))/x^6,x]

[Out]

(Sqrt[d + e*x^2]*(-15*a*(3*d^2 + d*e*x^2 - 2*e^2*x^4) + b*c*Sqrt[1 + 1/(c^2*x^2)]*x*(-31*e^2*x^4 + d*e*x^2*(8
- 19*c^2*x^2) + 3*d^2*(3 - 4*c^2*x^2 + 8*c^4*x^4)) - 15*b*(3*d^2 + d*e*x^2 - 2*e^2*x^4)*ArcCsch[c*x]))/(225*d^
2*x^5) + ((I/225)*b*c*Sqrt[1 + 1/(c^2*x^2)]*x*Sqrt[1 + (e*x^2)/d]*(c^2*d*(24*c^4*d^2 - 19*c^2*d*e - 31*e^2)*El
lipticE[I*ArcSinh[Sqrt[c^2]*x], e/(c^2*d)] + (-24*c^6*d^3 + 31*c^4*d^2*e + 23*c^2*d*e^2 - 30*e^3)*EllipticF[I*
ArcSinh[Sqrt[c^2]*x], e/(c^2*d)]))/(Sqrt[c^2]*d^2*Sqrt[1 + c^2*x^2]*Sqrt[d + e*x^2])

________________________________________________________________________________________

fricas [F]  time = 0.71, size = 0, normalized size = 0.00 \[ {\rm integral}\left (\frac {\sqrt {e x^{2} + d} {\left (b \operatorname {arcsch}\left (c x\right ) + a\right )}}{x^{6}}, x\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a+b*arccsch(c*x))*(e*x^2+d)^(1/2)/x^6,x, algorithm="fricas")

[Out]

integral(sqrt(e*x^2 + d)*(b*arccsch(c*x) + a)/x^6, x)

________________________________________________________________________________________

giac [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {\sqrt {e x^{2} + d} {\left (b \operatorname {arcsch}\left (c x\right ) + a\right )}}{x^{6}}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a+b*arccsch(c*x))*(e*x^2+d)^(1/2)/x^6,x, algorithm="giac")

[Out]

integrate(sqrt(e*x^2 + d)*(b*arccsch(c*x) + a)/x^6, x)

________________________________________________________________________________________

maple [F]  time = 0.43, size = 0, normalized size = 0.00 \[ \int \frac {\left (a +b \,\mathrm {arccsch}\left (c x \right )\right ) \sqrt {e \,x^{2}+d}}{x^{6}}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((a+b*arccsch(c*x))*(e*x^2+d)^(1/2)/x^6,x)

[Out]

int((a+b*arccsch(c*x))*(e*x^2+d)^(1/2)/x^6,x)

________________________________________________________________________________________

maxima [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \frac {1}{15} \, a {\left (\frac {2 \, {\left (e x^{2} + d\right )}^{\frac {3}{2}} e}{d^{2} x^{3}} - \frac {3 \, {\left (e x^{2} + d\right )}^{\frac {3}{2}}}{d x^{5}}\right )} + \frac {1}{15} \, b {\left (\frac {{\left (2 \, e^{2} x^{4} - d e x^{2} - 3 \, d^{2}\right )} \sqrt {e x^{2} + d} \log \left (\sqrt {c^{2} x^{2} + 1} + 1\right )}{d^{2} x^{5}} - 15 \, \int \frac {{\left (2 \, c^{2} e^{2} x^{6} - c^{2} d e x^{4} + 3 \, {\left (5 \, d^{2} \log \relax (c) - d^{2}\right )} c^{2} x^{2} + 15 \, d^{2} \log \relax (c) + 15 \, {\left (c^{2} d^{2} x^{2} + d^{2}\right )} \log \relax (x)\right )} \sqrt {e x^{2} + d}}{15 \, {\left (c^{2} d^{2} x^{8} + d^{2} x^{6}\right )}}\,{d x} + 15 \, \int \frac {{\left (2 \, c^{2} e^{2} x^{4} - c^{2} d e x^{2} - 3 \, c^{2} d^{2}\right )} \sqrt {e x^{2} + d}}{15 \, {\left (c^{2} d^{2} x^{6} + d^{2} x^{4} + {\left (c^{2} d^{2} x^{6} + d^{2} x^{4}\right )} \sqrt {c^{2} x^{2} + 1}\right )}}\,{d x}\right )} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a+b*arccsch(c*x))*(e*x^2+d)^(1/2)/x^6,x, algorithm="maxima")

[Out]

1/15*a*(2*(e*x^2 + d)^(3/2)*e/(d^2*x^3) - 3*(e*x^2 + d)^(3/2)/(d*x^5)) + 1/15*b*((2*e^2*x^4 - d*e*x^2 - 3*d^2)
*sqrt(e*x^2 + d)*log(sqrt(c^2*x^2 + 1) + 1)/(d^2*x^5) - 15*integrate(1/15*(2*c^2*e^2*x^6 - c^2*d*e*x^4 + 3*(5*
d^2*log(c) - d^2)*c^2*x^2 + 15*d^2*log(c) + 15*(c^2*d^2*x^2 + d^2)*log(x))*sqrt(e*x^2 + d)/(c^2*d^2*x^8 + d^2*
x^6), x) + 15*integrate(1/15*(2*c^2*e^2*x^4 - c^2*d*e*x^2 - 3*c^2*d^2)*sqrt(e*x^2 + d)/(c^2*d^2*x^6 + d^2*x^4
+ (c^2*d^2*x^6 + d^2*x^4)*sqrt(c^2*x^2 + 1)), x))

________________________________________________________________________________________

mupad [F]  time = 0.00, size = -1, normalized size = -0.00 \[ \int \frac {\sqrt {e\,x^2+d}\,\left (a+b\,\mathrm {asinh}\left (\frac {1}{c\,x}\right )\right )}{x^6} \,d x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(((d + e*x^2)^(1/2)*(a + b*asinh(1/(c*x))))/x^6,x)

[Out]

int(((d + e*x^2)^(1/2)*(a + b*asinh(1/(c*x))))/x^6, x)

________________________________________________________________________________________

sympy [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {\left (a + b \operatorname {acsch}{\left (c x \right )}\right ) \sqrt {d + e x^{2}}}{x^{6}}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a+b*acsch(c*x))*(e*x**2+d)**(1/2)/x**6,x)

[Out]

Integral((a + b*acsch(c*x))*sqrt(d + e*x**2)/x**6, x)

________________________________________________________________________________________